MCS 012 Solved Assignment

Course Code
:
MCS-012
Course
Title
:
Computer
Organisation and Assembly
Language
Programming
Assignment
Number
:
MCA(I)/012/Assignment/15-16
Maximum Marks
:
100
Weightage
:
25%
Last Dates for
Submission
:
15th October, 2015 (For July 2015
Session)
15th April, 2016 (For January 2016
Session)
There are four questions in this
assignment, which carries 80 marks. Rest 20 marks are for viva voce. You may
use illustrations and diagrams to enhance the explanations. Please go through
the guidelines regarding assignments given in the Programme Guide for the
format of presentation. Answer to each part of the question should be confined
to about 300 words.
or
1. (Covers
Block 1)
(a)
Perform the following
arithmetic operations using binary signed 2’s
(3 Marks)
complement notation for
integers. You may assume that the
maximum size of integers is
of  8 bits including the sign
bit. (Please
note that the
numbers given here are in decimal notation)
i)  Add – 128 and 120
ii) Subtract 124 from –99
iii) Add 64 and 61
Please indicate the overflow if
it is occurs. Also write, how you
have identified the overflow.
(b)
Convert the
hexadecimal number: ( FAEBDC)h  into equivalent
(1 Marks)
binary, octal
and decimal.
(c)
Convert the following string
into equivalent “UTF 16” code –
(2 Marks)
“You may assume that Hindi
swar starts with
Are these UTF 16 codes similar
as that used in ASCII?
(d)
Use a Karnaugh’s map to design
a circuit that takes four input bits
(2 Marks)
and produces one output bit.
The output bit is 0 if the first and
fourth input
are same else it is 1.
(e)
An 8 bit data 01101101 after
transmission is received as 01001101.
(3 Marks)
Explain how SEC code will
detect and correct this problem.
(f)
Design a two bit counter (a
sequential circuit) that counts from 00
(5 Marks)
to 10 only. Thus, the counter
states are 00, 01, 10, 00, 01, …. You
should show the state table,
state diagram, the k-map for circuit
design
and logic diagram of the resultant design using D flip-flop or J-K flip flop.


4


(g)    Explain
the double precision floating point IEEE 754                               (4
Marks)
representation.
Represent the number (124.0625)10 using IEEE 754
single precision and
double precision representations.
2. (Covers Block
2)
(a)    A RAM
has a capacity of 8192K having the word size of 16 bits             (2 Marks)
and supports byte
addresses only.
(i)          
How many data input and output lines
does this RAM need? Explain your answer.
(ii)        
How
many address lines will be needed for this RAM? Explain.
(b)    A
computer has 1MB RAM and has word size of 16 bits. It has               (4 Marks)
cache memory having 16 blocks
with a block size of 32 bits. Explain
how a main memory address will be
mapped to a cache address, if
(i)     Direct cache mapping is used
(ii)    Associative cache mapping is used
(iii)    
Two
way set associative mapping scheme is used.
(c)   Compare
and contrast the features of Interrupt driven I/O with that of (4 Marks)
DMA. Which I/O technique will be preferable in the following
situations. Give
justification in support of your answer.
(i)         
Data is to be transferred from a very
high speed device having high volume data.
(ii)       
Small
volume of data transferred asynchronously.
(d)
Explain the term FAT in the
context of disk operating system.
(2 Marks)
What will be the size of a disk
and its FAT, if a disk has 64 tracks
with each track having 16
sectors and size of each sector is 512
byte? You may
take the cluster size as 4 sectors.
(e)
Explain the characteristics of
at least two portable
(2 Marks)
secondary/tertiary storage
devices.
(f)
Define each of the following
terms. Also explain their use/advantage,
(6 Marks)
if needed.
(Word limit
for answer of each part is 50 words ONLY)
(i)
Access time on magnetic disks
(ii)
Backup devices
(iii)
Scanner resolution
(iv)
LCD and its types
(v)
AGP in the context of video
card interfaces
(vi)
Colour Depth
5


3. (Covers Block
3)
(a)    A
hypothetical machine has 22 registers. Out of these 6 registers              (4 Marks)
are
used as segment registers. Assume that the machine uses segment registers to
find physical address in the similar way as is done in 8086 processor.
Remaining 16 registers are general purpose registers. All the registers and
memory word for the machine are of 16 bits. The machine has 1 M Word RAM. An
instruction of the machine is of 32 bits which includes opcode – 5 bits,
addressing mode specification – 3 bits and remaining bits for specifying the
operand addresses. Each instruction contains at most two operand addresses – at
most one memory operand and remaining register operand(s). What would be the
size of memory address, if direct addressing is used? What would be the size of
the direct register operand? The machine is to be used for calculations
involving arrays and floating point numbers. Design five different types of
addressing modes for this machine. Give justification of the selection of every
addressing mode.
(b)        
Assume that the machine as stated in
part (a) has named 5 of its (5 Marks) general purpose registers based on
their possible role in instruction
execution
as Program Counter (PC), Accumulator (AC), Memory Address Register (MAR),
Instruction Register (IR) , Data Register (DR) and Flag registers (FR). To
execute an instruction of the machine that has a direct memory operand and a
register operand, the memory operand is first brought into the DR register and
the register operand is transferred to AC register. The result of the operation
is stored in the AC register. One of the instruction of the machine is given
below:
ADD R1, X               // this instruction adds the
operand stored in
Register R1 and memory location
X. The result
is stored in the AC
register.
Write
and explain the sequence of micro-operations that are required to fetch and
execute this instruction. Make and state suitable assumptions, if any.
(c)    Assume that you have a machine as shown in
section 3.2.2 of Block        (2 Marks)
3 having the micro-operations as
given in Figure 10 on page 62 of
Block 3. Consider that R1 and R2
both are 8 bit registers and
contains 1010 0011 and 11001011
respectively. What will be the
values of select inputs,
carry-in input and result of operation
(including carry out bit) if the
following micro-operations are
performed? (For each
micro-operation you may assume the initial
value of R1 and R2 as given
above)
(i)     Subtract R2 from R1
(ii)    AND of R1 and R2
(iii) Shift right R1 twice
(iv)  Add R1 and R2 with carry
6


(d)
How does a Micro-programmed
control Unit will control the
(3 Marks)
execution of an instruction.
Explain with the help of an addition
instruction.
(e)
Explain with the help of a
diagram how does RISC Instruction
(3 Marks)
pipelining work. Also explain
how RISC instruction pipeline can
be optimised.
(f)
Assume that a RISC machine has
128 registers out of which 16
(3 Marks)
registers are reserved for the
Global variables and 16 for
Instruction
related tasks. This machine has been designed to have
12 registers for storing four
input parameters, four output
parameters and
four local variables for a subroutine call. Explain
with the help of a diagram, how
the overlapped register window
can be
implemented in this machine for procedure calls. You must
explain how the parameters will
be passed, if a subroutine calls
another
subroutine.
4. (Covers
Block 4)
(a)
Write a program in 8086
assembly Language (with proper
(8 Marks)
comments) to count the number
of alphabets ‘a’, ‘e’ and ‘o’
(irrespective
of lower or upper case) in a strings. For example, in
case the strings is:
“ABaDEFeHIO” the count of ‘a’ will be 2, ‘e’ is
2 and ‘o’ is
1. You may assume that string is available in the
memory and is of length 10.
Make suitable assumptions, if any.
(b)
Write a program in 8086
assembly language that accepts a 2 digit
(6 Marks)
input from the keyboard (as
ASCII input) into packed BCD number.
The packed BCD
number may be stored in memory.
(c)
Write a simple near procedure
in 8086 assembly language that
(6 Marks)
receives an ASCII digit as
parameter. It returns 1 if the ASCII digit is
‘Z’ else it returns 0. Make
suitable assumptions, if any.

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