[Solved]: Can there exist a recurrence relation for “sequential search”?

Problem Detail: I’m just confused, cause from my knowledge recurrence is applied mostly to recursive procedures or divide and conquer techniques etc.

Asked By : Sameer Thigale

Answered By : David Richerby

Sure. The cost of searching a list of length zero is zero; the worst-case cost of searching a list of length $n$ is one greater than the cost of searching a list of length $n-1$. So $$begin{align*}T(0)&=0 T(n)&=T(n-1)+1,,end{align*}$$ with solution being, as you’d expect, $T(n)=n$.
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