Problem Detail: The question is:
Consider a virtual address space of 256 pages with page size of 4KB, mapped onto a physical memory of 128 frames. How many total bits are required in the virtual address? How many total bits are required in the physical address?
I can’t figure out how to number of frames is used with the number of pages to find the bits required. Can someone explain the steps required to solve this problem?
Asked By : user3233721
Answered By : Greg Miller
You sound like you’re studying for the same finals as me :). The bits for the virtual address can be calculated as $$log_2( page size * number of pages )$$ For the physical the computation is, essentially the same $$log_2( page size * number of frames )$$ In this case, 20 and 19 respectively.
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Question Source : http://cs.stackexchange.com/questions/41971
